# What is Maxwell’s mesh current method?| What is Maxwell’s mesh current method?

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## Maxwell’s Mesh Section Method | Maxwell’s mesh current method

In this rule, Kirchhoff’s voltage The rule applied to a network is to write the mesh equation in reams of mesh current rather than branch current, with each mesh assigned a different mesh current. This mesh current flows clockwise around the perimeter of the mesh without splitting into branch currents at a junction.

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Kirchhoff’s voltage law is applied to write the equation in terms of unknown trap currents. The branch currents are then found by taking the algebraic sum of the mesh currents common to that branch.

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*Maxwell’s mesh current method consists of the following steps:-*

- A different mesh current is assigned to each mesh. For convenience, all lattice currents are assumed to flow clockwise. For example, in Figure 3.6, the mesh currents are given to ABDA and BCDB, respectively.
_{1}and I_{2}have been assigned. - If two trap currents are flowing through a circuit element, the actual current in the circuit element is the algebraic sum of the two. Thus in Fig. 3.6, there are two mesh currents.
_{1}and I_{2}which R_{2}flows in. If we go from B to D, then current I_{1}– I_{2}Is. And if we go in the other direction (i.e., from D to B), then the current l_{2}– I_{1}Is. - Kirchhoff’s voltage law is applied to write the equation for each trap in terms of trap currents. Remember, when writing the Aries equation, an increase in potential is assigned a positive sign and a decline in potential negative sign.
- If the value of a mesh current in the solution turns out to be negative, it means that the true direction of that mesh current is counterclockwise, that is, opposite the assumed clockwise direction.

Applying Kirchhoff’s voltage law in Fig. 3.6, we have

*mesh abda. – I*_{1}*R*_{1}* – (I*_{1}* – I*_{2}*)R*_{2}* + E*_{1}* = 0 *

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*Or I1(R1 + R2) – I2R*_{2}* = E*_{1}

* mesh BCDB. – I*_{2}*R*_{3}* – E*_{2}* – (I*_{2}* – I*_{1}*)R2 = 0 *

*Or – I*_{1}*R*_{2}* + (R)*_{2}* + R*_{3}*) I*_{2}* = – E*_{2}

Solving equations (i) and (ii), the mesh currents_{1} and I_{2} can be detected, once the mesh currents are known, branch currents can be obtained easily. The advantage of this method is that it usually reduces the number of equations to solve the network problem.

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